20x^2+x+.08=0

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Solution for 20x^2+x+.08=0 equation: 



20x^2+x+.08=0

We add all the numbers together, and all the variables

20x^2+x+0.08=0

a = 20; b = 1; c = +0.08;
Δ = b2-4ac
Δ = 12-4·20·0.08
Δ = -5.4
Delta is less than zero, so there is no solution for the equation

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